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A17, A21Linear equations

Edexcel GCSE Maths (1MA1), Higher tier · Algebra

Practise Linear equations. unlimited generated questions on this subtopic, at up to four difficulty levels, with full mark schemes and a progress tracker. Free, no account needed.

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Sample questions

Written for this site in the style of Edexcel exam questions. They are not taken from real past papers.

Question 1Easy2 marks
Solve \(4t - 2 = 2t - 4\)[2]
Show the answer and mark scheme
Answer: \(t = -1\)
  • M1 for \(2t = -2\) oe (terms in \(t\) on one side and numbers on the other)
  • A1 for \(t = -1\)

Worked solution: \(4t - 2 = 2t - 4\)
\(2t = -2\)
\(t = -1\)

Question 2Medium3 marks
Solve \(10 - 4(y - 3) = y + 27\)
You must show all your working.[3]
Show the answer and mark scheme
Answer: \(y = -1\)
  • M1 for expanding the bracket correctly: \(10 - 4y + 12 = y + 27\)
  • M1 for \(5y = -5\) oe
  • A1 for \(y = -1\)

Worked solution: \(22 - 4y = y + 27\)
\(5y = -5\)
\(y = -1\)

Question 3Hard4 marks
Solve \(\frac{2n + 11}{5} - \frac{n + 13}{2} = -4\)
You must show all your working.[4]
Show the answer and mark scheme
Answer: \(n = -3\)
  • M1 for multiplying every term by \(10\) (or a multiple of \(10\)), e.g. \(2(2n + 11) - 5(n + 13) = -40\)
  • M1 for expanding the brackets correctly, e.g. \(4n + 22 - (5n + 65) = -40\)
  • M1 for \(-n = 3\) oe
  • A1 for \(n = -3\)

Worked solution: \(2(2n + 11) - 5(n + 13) = -40\)
\(-n - 43 = -40\)
\(-n = 3\), so \(n = -3\)

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