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P2.2Surds

Edexcel A level Maths (9MA0) · Pure mathematics › Algebra and functions

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Sample questions

Written for this site in the style of Edexcel exam questions. They are not taken from real past papers.

Question 1Easy4 marks
In this question you must show all stages of your working.
Solutions relying entirely on calculator technology are not acceptable.
(a) Simplify fully \(\sqrt{252} + \sqrt{28} - \sqrt{112}\), giving your answer in the form \(k\sqrt{7}\), where \(k\) is an integer.[2]
(b) Expand and simplify \((4 - 4\sqrt{11})(6 - 2\sqrt{11})\), giving your answer in the form \(a + b\sqrt{11}\), where \(a\) and \(b\) are integers.[2]
Show the answer and mark scheme
(a) Answer: \(4\sqrt{7}\)
  • M1 for at least two of \(\sqrt{252} = 6\sqrt{7}\), \(\sqrt{28} = 2\sqrt{7}\), \(\sqrt{112} = 4\sqrt{7}\)
  • A1 for \(4\sqrt{7}\)

Worked solution: \(\sqrt{252} = \sqrt{36 \times 7} = 6\sqrt{7}\)
\(\sqrt{28} = \sqrt{4 \times 7} = 2\sqrt{7}\)
\(\sqrt{112} = \sqrt{16 \times 7} = 4\sqrt{7}\)
\(\sqrt{252} + \sqrt{28} - \sqrt{112} = 6\sqrt{7} + 2\sqrt{7} - 4\sqrt{7} = 4\sqrt{7}\)

(b) Answer: \(112 - 32\sqrt{11}\)
  • M1 for an attempt to expand the brackets with at least three of the four terms correct: \(24 - 8\sqrt{11} - 24\sqrt{11} + 88\)
  • A1 for \(112 - 32\sqrt{11}\)

Worked solution: \((4 - 4\sqrt{11})(6 - 2\sqrt{11}) = 24 - 8\sqrt{11} - 24\sqrt{11} + 88 = 112 - 32\sqrt{11}\), using \((\sqrt{11})^2 = 11\).

Question 2Medium4 marks
In this question you must show all stages of your working.
Solutions relying entirely on calculator technology are not acceptable.
Express \(\frac{6 - 4\sqrt{7}}{3 - \sqrt{7}}\) in the form \(p + q\sqrt{7}\), where \(p\) and \(q\) are integers.[4]
Show the answer and mark scheme
Answer: \(-5 - 3\sqrt{7}\)
  • M1 for multiplying numerator and denominator by \(3 + \sqrt{7}\)
  • M1 for expanding the numerator with at least three of the four terms correct: \(18 + 6\sqrt{7} - 12\sqrt{7} - 28\)
  • A1 for \(\frac{-10 - 6\sqrt{7}}{2}\) or equivalent unsimplified correct fraction
  • A1 for \(-5 - 3\sqrt{7}\)

Worked solution: \(\frac{6 - 4\sqrt{7}}{3 - \sqrt{7}} \times \frac{3 + \sqrt{7}}{3 + \sqrt{7}}\)
Numerator: \((6 - 4\sqrt{7})(3 + \sqrt{7}) = 18 + 6\sqrt{7} - 12\sqrt{7} - 28 = -10 - 6\sqrt{7}\)
Denominator: \((3 - \sqrt{7})(3 + \sqrt{7}) = 9 - 7 = 2\)
So the expression is \(\frac{-10 - 6\sqrt{7}}{2} = -5 - 3\sqrt{7}\).

Question 3Hard5 marks
In this question you must show all stages of your working.
Solutions relying entirely on calculator technology are not acceptable.
Solve the equation
\(x^2 - 9\sqrt{5}x + 90 = 0\)
giving your answers in the form \(k\sqrt{5}\), where \(k\) is an integer.[5]
Show the answer and mark scheme
Answer: \(x = 3\sqrt{5}, \ x = 6\sqrt{5}\)
  • M1 for use of the quadratic formula (or completing the square) with \(a = 1\), \(b = -9\sqrt{5}\), \(c = 90\)
  • A1 for \(b^2 - 4ac = 405 - 360 = 45\)
  • M1 for simplifying \(\sqrt{45} = 3\sqrt{5}\)
  • A1 for one correct root
  • A1 for both roots: \(x = 3\sqrt{5}\) and \(x = 6\sqrt{5}\)

Worked solution: \(x = \frac{9\sqrt{5} \pm \sqrt{45}}{2} = \frac{9\sqrt{5} \pm 3\sqrt{5}}{2}\)
So \(x = 3\sqrt{5}\) or \(x = 6\sqrt{5}\).

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