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3.3.1Percentage yield

AQA GCSE Chemistry (8462), Higher tier · Quantitative chemistry › Yield and atom economy

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A reaction has a maximum theoretical yield of 12.0 g. A student obtains 9.0 g of product.
Calculate the percentage yield.
75%

Sample questions

Written for this site in the style of AQA exam questions. They are not taken from real past papers.

Question 1Easy4 marks
The percentage yield of a reaction can be calculated using the equation:
percentage yield = (mass of product actually made ÷ maximum theoretical mass of product) × 100
(a) A student made 4.2 g of a product. The maximum theoretical mass of the product was 5.0 g.
Calculate the percentage yield.[2]
(b) Give two reasons why the percentage yield of a reaction is often less than 100%.[2]
Show the answer and mark scheme
(a) Answer: 84%
  • (4.2 ÷ 5.0) × 100
  • 84 (%)
(b)
  • the reaction may be reversible / may not go to completion
  • some of the product may be lost when it is separated from the reaction mixture
  • some of the reactants may react in ways different from the expected reaction / side reactions
Question 2Medium5 marks
A student made crystals of zinc sulfate from zinc oxide and dilute sulfuric acid.
The maximum theoretical mass of zinc sulfate crystals was 16.1 g. The student made 11.3 g of crystals.
(a) Calculate the percentage yield.
Give your answer to 3 significant figures.[2]
(b) Suggest two ways in which some of the zinc sulfate could have been lost during the practical.[2]
(c) Ammonia is made by the Haber process:
N2 + 3H2 ⇌ 2NH3
Explain why the yield of ammonia can never be 100%.[1]
Show the answer and mark scheme
(a) Answer: 70.2%
  • (11.3 ÷ 16.1) × 100
  • 70.2 (%)
(b)
  • some solution left in the beaker / soaked into the filter paper during filtering
  • some solution spat out / splashed during heating / evaporation
  • some crystals left on the filter paper or stuck to the apparatus
  • not all of the zinc sulfate crystallised / some stayed dissolved in the remaining solution
(c)
  • the reaction is reversible, so it does not go to completion / some ammonia breaks down back into nitrogen and hydrogen
Question 3Hard6 marks
The fertiliser ammonium nitrate is made by reacting ammonia with nitric acid:
NH3 + HNO3 → NH4NO3
Relative atomic masses (Ar): H = 1, N = 14, O = 16
(a) Calculate the maximum theoretical mass of ammonium nitrate that can be made from 34 tonnes of ammonia.[2]
(b) The percentage yield of the process is 95%.
Calculate the actual mass of ammonium nitrate made from 34 tonnes of ammonia.[1]
(c) A factory needs to make 200 tonnes of ammonium nitrate. The percentage yield is 95%.
Calculate the mass of ammonia needed.
Give your answer to 3 significant figures.[3]
Show the answer and mark scheme
(a) Answer: 160 tonnes
  • 17 tonnes of NH3 produce 80 tonnes of NH4NO3 / (34 ÷ 17) × 80
  • 160 (tonnes)
(b) Answer: 152 tonnes
  • 152 (tonnes)
(c) Answer: 44.7 tonnes
  • theoretical mass needed = 200 ÷ 0.95 = 210.5 (tonnes)
  • mass of ammonia = 210.5 × 17 ÷ 80
  • 44.7 (tonnes)

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